Berkson’s paradox: Making psychics seem real

Today I discovered this really lovely little thing called Berkson’s paradox. It’s one of those paradoxes that isn’t actually a paradox, it just seems initially crazy. (It turns out that there’s a name for that kind of paradox!)

Say you’re flipping a coin. Sometimes it comes up heads, sometimes tails. I claim to be psychic, and I make predictions about what your coin flip is going to be. You, being statistically minded, decide to keep track of how well I’m doing: very many times, you flip a coin, hide the result from me, I guess whether it’s heads or tails, and then you record the true answer and my guess.

To show that I’m not psychic, you could show that the probability that I call “heads” does not depend on whether you actually flipped heads or tails. Formally, the probability that I call “heads” is independent of whether you flip heads. Let \(H_c\) be the event where the coin falls heads, and let \(H_p\) be the event where the psychic (me) calls heads. Then your claim is that \(P(H_p | H_c) = P(H_p)\), that is, that the probability that I call “heads” is the same whether the coin is actually heads or not.

Note that if the first quantity were greater, then I’m more likely to call heads when the coin lands heads, that is, I’m actually capable of some divination. (If the second quantity were greater, then I’m actually capable of divination, I’m just doing it backwards, more often calling “heads” when it’s tail. I would say this means that your negative energy is causing my mental image of the coin to “flip” from heads to tails and vice versa. I would still be predicting something!)

Having been confronted with your null result, which showed that my predictions have no bearing on the real state of the coin, I claim that the negative energy of the tails was mucking up my predictions, and I ask you to exclude cases where I correctly guessed tails. In other words, I ask you to only consider cases where the coin was heads and/or I called heads. Mathematically, I’m asking you to compare \(P(H_p | H_c \text{ and } H_c \cup H_p)\) against \(P(H_p | H_c \cup H_p)\).

If you looked at the numbers from our very large trial, you would find that the second quantity is larger: it looks like I’m doing (reversed) divination! Mathematically, this shakes out fairly easily: because \(H_c\) implies \(H_p \cup H_c\), the first quantity in this second comparison is just \(P(H_p | H_c)\), which we previously showed was just \(P(H_p)\). It’s now clear that the second quantity will be larger: the probability that I call heads given that I called heads and/or you flipped heads is greater than the probability that I call heads in general. So this is a “paradox” only insofar as my request to exclude the tails-tails causes seemed right to your (incorrect) intuition.

This may sound silly and arcane because I told a story about psychics, but consider this much more real idea: say you’re curious if white people are more likely to be promoted in your company. You interview white people who got promoted, non-white people who got promoted, and non-white people who didn’t get promoted. Then you look for an association between being white and getting promoted.

Now imagine that race had no effect on getting promoted. (Clearly, this is still an unreal example, but wait for the punchline.) Then let non-whiteness be like the psychic’s calling “heads” and being promoted be like the coin actually falling heads. You interviewed only people who got promoted and/or are non-white, which is like including the tails-tails cases. Thus, Berkson’s paradox shows that you will measure a negative relationship between being non-white and being promoted. In other words, by excluding white people who didn’t get promoted, you will falsely conclude that being white does make you more likely to be promoted. Weird, right?

Here’s another example: you have two friends who rank movies on a 1 to 10 scale. You only want to watch the best movies, so you decide to consider only those movies where the sum of their two scores is 14. If their recommendations were independent, then they might comment on 100 movies and create a perfect grid: one movie where A voted 1 and voted 1, another movie where voted 1 and B voted 2, and so on. Selecting only those movies with a combined score of at least 14 selects for the upper-right quadrant, among which their scores are negatively correlated: you get the erroneous sense that A and B have non-overlapping tastes, when if fact they are completely independent.

Leave a Reply

Your email address will not be published / Required fields are marked *